InStrRev Function
Returns the position of an occurrence of one string within another, from the
end of string.
InStrRev(string1, string2[, start[,
compare]])
Arguments
string1
Required. String expression being searched.
string2
Required. String expression being searched for.
start
Optional. Numeric expression that sets
the starting position for each search. If omitted, -1 is used, which means that
the search begins at the last character position. If start contains Null,
an error occurs.
compare
Optional. Numeric value indicating the kind of comparison to use
when evaluating substrings. If omitted, a binary comparison is performed. See
Settings section for values.
Settings
The compare argument can have the following values:
| Constant | Value | Description | | vbBinaryCompare | 0 | Perform a binary comparison. | | vbTextCompare | 1 | Perform a textual comparison. |
Return Values
InStrRev returns the following values:
| If | InStr returns | | string1 is zero-length | 0 | | string1 is Null | Null | | string2 is zero-length | start | | string2 is Null | Null | | string2 is not found | 0 | | string2 is found within string1 | Position at which match is found | | start > Len(string2) | 0 |
Remarks
The following examples use the InStrRev function to search a string:
Dim SearchString, SearchChar, MyPos
SearchString ="XXpXXpXXPXXP" ' String to search in.
SearchChar = "P" ' Search for "P".
MyPos = InstrRev(SearchString, SearchChar, 10, 0) ' A binary comparison starting at position 10. Returns 9.
MyPos = InstrRev(SearchString, SearchChar, -1, 1) ' A textual comparison starting at the last position. Returns 12.
MyPos = InstrRev(SearchString, SearchChar, 8) ' Comparison is binary by default (last argument is omitted). Returns 0.
Note The syntax for the InStrRev function is not the same as the syntax for the InStr function.
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